Web21 de jun. de 2024 · A set of a direction and a value. eg. heading (direction) and speed together give a velocity. How a vector is expressed depends on what the coordinate system is, and how many dimensions are taken into consideration. <35°, 12> is a two dimensional polar vector, where <14, 9, -20> is a three dimensional Cartesian vector. Web25 de ago. de 2024 · If K is a large number, it means that the equilibrium concentration of the products is large. In this case, the reaction as written will proceed to the right (resulting in an increase in the concentration of products) If K is a small number, it means that the equilibrium concentration of the reactants is large.
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Web22 de fev. de 2014 · On Kerbin (left), anything below ~18km of altitude will be considered flying over (that is, Lower Atmosphere). Outer Space on Kerbin starts at ~250km. The shift from Upper Atmosphere to Near Space is the edge of Kerbin's atmosphere (~69km), and (as detailed above) may depend on the trajectory. On the Mun (middle), there is … Web4 de jul. de 2024 · Flying High: in the upper atmosphere, if and only if an atmosphere is present; ... As of KSP version 1.0.2, ... eventually gathering all science that can be gathered from orbit. For example, with the Mun this means a polar orbit of 90 degrees, with a periapsis of 20 Km and an apoapsis of 620 Km. china town helsingborg
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WebYes. K = [product]/ [reactant], so the higher the concentration of ions dissolved from the soluble reactant, the higher the Ksp and solubility. 4 skywalker456 • 4 yr. ago No, you look at molar solubility (X) no Ksp to determine the degree of solubility. The higher the X, the more soluble the salt or substance is. 4 shidru • 4 yr. ago That's right. WebThis increased partial pressure means that more gas particles will enter the liquid (there is therefore less gas above the liquid, so the partial pressure decreases) in order to alleviate the stress created by the increase in pressure, resulting in greater solubility. WebISP is your engine's specific impulse. Force = mass x velocity squared. So the faster and straighter an engine can eject the material then the engine can exert more force for expelling the same amount of material. For your rockets, higher ISP will result in more Delta v for the same amount of fuel. Delta v = ISP x 9.81m/s (wet mass / dry mass) chinatown harvard il